JEE Main & Advanced Mathematics Permutations and Combinations Question Bank Definition of permutation, Number of permutations with or without repetition, Conditional permutations

  • question_answer
    How many numbers lying between  999 and 10000 can be formed with the help of the digit 0,2,3,6,7,8 when the digits are not to be repeated [AMU 2005]

    A) 100

    B) 200

    C) 300

    D) 400

    Correct Answer: C

    Solution :

    The numbers between 999 and 10000 are of four digit numbers. The four digit numbers formed by digits 0, 2, 3, 6, 7, 8 are\[^{6}{{P}_{4}}=360\]. But here those numbers are also involved which begin from 0. So we take those numbers as three digit numbers. Taking initial digit 0, the number of ways to fill remaining 3 places from five digits 2, 3, 6, 7, 8 are \[^{5}{{P}_{3}}=60\] So the required numbers = 360-60 = 300.


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