A) \[(3,\,1),(-7,\,11)\]
B) \[(3,\,1),(7,\,11)\]
C) \[(-3,\,1),(-7,\,11)\]
D) \[(1,\,3),(-7,\,11)\]
Correct Answer: A
Solution :
Let the point (h, k) then \[h+k=4\] ..?(i) and \[1=\pm \frac{4h+3k-10}{\sqrt{{{4}^{2}}+{{3}^{2}}}}\Rightarrow 4h+3k=15\] ?..(ii) and \[4h+3k=5\] ?..(iii) On solving (i) and (ii); and (i) and (iii), we get the required points (3, 1) and (?7, 11). Trick: Check with options. Obviously, points (3, 1) and (-7, 11) lie on \[x+y=4\]and perpendicular distance of these points from \[4x+3y=10\]is 1.You need to login to perform this action.
You will be redirected in
3 sec