A) A-4 B-1 C-3 D-2
B) A-3 B-2 C-4 D-1
C) A-2 B-1 C-4 D-3
D) A-2 B-3 C-4 D-1
Correct Answer: A
Solution :
Here, A. 12\[\div \]4 = 3 as 4 x 3 = 12 or 4 groups of 3 B. 12\[\div \]6 = 2 as 6 x 2 = 12 or 6 groups of 2 C. 12\[\div \]3 = 4 as 3 x 4 = 12 or 3 groups of 4 D. 12\[\div \]2 = 6 as 2 x 6 = 12 or 2 groups of 6 Thus. The order is A\[\to \]4. B\[\to \]1, C\[\to \]3, D\[\to \]2. Therefore the answer is option (a) 4132
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