Answer:
By Einstein's photo-electric equation, \[{{W}_{0}}=hv-{{K}_{\max }}\] For surface P, the photo-electrons have zero kinetic energy while for surface \[\text{Q}\], the photo-electrons have some kinetic energy. It follows from the above equation that the surface P has a higher work function \[{{W}_{0}}\] than the surface \[\text{Q}\]. If the incident frequency v is slightly reduced, the energy of the incident photon will become less than the work function \[{{\text{W}}_{0}}\] of the surface P. There will be no photo-electric emission from surface P. In case of surface \[Q\] the kinetic energy of photo-electrons will decrease.
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