question_answer

Figure shows three charges \[+2q,-q\] and\[+3q\]. Two charges \[+2q\] and \[-q\] are enclosed with in a surface 'S'. What is the electric flux due to this configuration through the surface 'S'?       

Answer:

                \[{{\phi }_{E}}=\frac{\text{Net chage enclosed by the surface S}}{{{\varepsilon }_{0}}}\]                 \[=\frac{+2q-q}{{{\varepsilon }_{0}}}=\frac{q}{{{\varepsilon }_{0}}}\]