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10th Class Science Electricity and Circuits Question Bank Electricity

  • question_answer
    If a resistance 5Q is connected in the left gap of a meter bridge and 15Q in the other gap then position of balancing point is

    A)  10 cm

    B)  20 cm

    C)  25 cm  

    D)  75 cm

    Correct Answer: C

    Solution :

                    \[\frac{R}{S}=\frac{l}{100-l}\] \[\therefore \]  \[\frac{5}{15}=\frac{l}{100-l}\] \[\Rightarrow \]               \[5(100-l)=15l\] \[\Rightarrow \]               \[500=15l+5l\] \[\Rightarrow \]               \[l=\frac{500}{20}=25\,\,cm\].


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