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10th Class Science Electricity and Circuits Question Bank Electricity

  • question_answer
    Resistance of a galvanometer coil is 600 ohms and a shunt is put in parallel to it. If only 1% of the main current passes through the galvanometer, then multiplying factor K is

    A)  10

    B)  100  

    C)  600

    D)  60

    Correct Answer: B

    Solution :

                    \[{{I}_{g}}=I\cdot \frac{S}{S+G}\] \[\therefore \]  \[1=100\times \frac{S}{S+600}\] \[\Rightarrow \]               \[S=\frac{600}{99}\] or            \[M.F.=\frac{S+G}{S}=\frac{\frac{600}{99}+600}{\frac{600}{99}}=100\Omega \]


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