A) 10 W
B) 40 W
C) 320 W
D) 160 W
Correct Answer: A
Solution :
If n identical bulbs are connected in series, to the rated voltage, the drop across each is\[\frac{V}{n}\]. So, the power consumed by each is\[\frac{P}{{{n}^{2}}}\]. Total power consumed by n such bulbs \[=n\times \frac{P}{{{n}^{2}}}=\frac{P}{n}=\frac{40}{4}\]
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