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10th Class Science Electricity and Circuits Question Bank Electricity

  • question_answer
    A student connects four 1/4 ohm cells in series but one cell has its terminals reversed. If each cell has an emf of \[1.5\] V and the external resistance is \[\text{2}\Omega \] , then the current flowing is

    A)  \[1\,\,A\]                             

    B)         \[1.5\,\,A\]

    C)  \[2.5\,\,A\]            

    D)         zero

    Correct Answer: A

    Solution :

                    \[\sum{V}=3E-E=2E=2\times 1\cdot 5=3\,\,volts\]                 \[\sum{R=4\times \frac{1}{4}+2=3\Omega }\]                     \[I=\frac{\sum{V}}{\sum{R}}=\frac{3}{3}=1\]


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