A) \[{{x}^{2}}+{{y}^{2}}={{(y-x)}^{2}}\]
B) \[{{x}^{2}}+{{y}^{2}}+{{(y-x)}^{2}}=0\]
C) \[{{x}^{2}}+{{y}^{2}}=4{{(y-x)}^{2}}\]
D) \[{{x}^{2}}+{{y}^{2}}+4{{(y-x)}^{2}}=0\]
Correct Answer: A
Solution :
Equation can be found by homogenising the curve w.r.t. line. i.e., \[{{x}^{2}}+{{y}^{2}}=4{{\left( \frac{y-x}{2} \right)}^{2}}\]or \[{{x}^{2}}+{{y}^{2}}={{(y-x)}^{2}}\].
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