A) \[abc(a+b+c)\]
B) \[3{{a}^{2}}{{b}^{2}}{{c}^{2}}\]
C) 0
D) None of these
Correct Answer: C
Solution :
\[\Delta =(b-a)\,(b-a)\,.\,\left| \,\begin{matrix} b & b-c & c \\ a & a-b & b \\ c & c-a & a \\ \end{matrix}\, \right|\] = \[{{(a-b)}^{2}}\left| \,\begin{matrix} b & b & c \\ a & a & b \\ c & c & a \\ \end{matrix}\, \right|\,=0\], [by \[{{C}_{2}}\to {{C}_{2}}+{{C}_{3}}\]] .
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