A) \[a+b+c\]
B) \[{{(a+b+c)}^{2}}\]
C) 0
D) \[1+a+b+c\]
Correct Answer: C
Solution :
\[\Delta =\left| \,\begin{matrix} 1 & a & b+c \\ 1 & b & c+a \\ 1 & c & a+b \\ \end{matrix}\, \right|=(a+b+c)\,\left| \,\begin{matrix} 1 & 1 & b+c \\ 1 & 1 & c+a \\ 1 & 1 & a+b \\ \end{matrix}\, \right|\] \[({{C}_{2}}\to {{C}_{2}}+{{C}_{3}})\] = 0, \[(\because \,\,{{C}_{1}}\equiv {{C}_{2}})\].
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