A) \[x=3,y=1\]
B) \[x=0,y=0\]
C) \[x=0,y=3\]
D) \[x=1,y=3\]
Correct Answer: B
Solution :
\[{{(a+b+c)}^{2}}\,\left| \,\begin{matrix} 2bc & -2c & -2b \\ {{b}^{2}} & c+a-b & 0 \\ {{c}^{2}} & 0 & a+b-c \\ \end{matrix}\, \right|\] \[\Rightarrow \] \[6i(-3+3)+3i(4i+20)+1(12-60i)=x+iy\] \[\Rightarrow \] \[({{C}_{1}}\to {{C}_{1}}+{{C}_{2}}+{{C}_{3}})\] \[\Rightarrow \] \[x=0,\,y=0\].
You need to login to perform this action.
You will be redirected in
3 sec
