A) \[0,\,\,12,\,\,12\]
B) 0, 12, -12
C) 0, 12, 16
D) 0, 9, 16
Correct Answer: B
Solution :
\[\left| \,\begin{matrix} 0 & x & 16 \\ x & 5 & 7 \\ 0 & 9 & x \\ \end{matrix}\, \right|\,=\,0\] By expanding, we get \[-x({{x}^{2}}-144)=0\] \[x=0\] or \[{{x}^{2}}=144\] \[\Rightarrow \] \[x=\pm 12\] So, \[x=0\], \[12,\]\[-12\].
You need to login to perform this action.
You will be redirected in
3 sec
