JEE Main & Advanced Mathematics Determinants & Matrices Question Bank Expansion of determinants, Solution of equation in the form of determinants and properties of determinants

  • question_answer
    The value of \[\left| \,\begin{matrix}    a & a+b & a+2b  \\    a+2b & a & a+b  \\    a+b & a+2b & a  \\ \end{matrix}\, \right|\]is equal to   [Kerala (Engg.) 2001]

    A) \[9{{a}^{2}}(a+b)\]

    B) \[9{{b}^{2}}(a+b)\]

    C) \[{{a}^{2}}(a+b)\]

    D) \[{{b}^{2}}(a+b)\]

    Correct Answer: B

    Solution :

    Operating\[{{C}_{1}}\to {{C}_{1}}+{{C}_{2}}+{{C}_{3}}\]. We get the value of given determinant as \[\left| \,\begin{matrix}    3a+3b & a+b & a+2b  \\    3a+3b & a & a+b  \\    3a+3b & a+2b & a  \\ \end{matrix}\, \right|\] = \[3\,(a+b)\,\left| \,\begin{matrix}    1 & a+b & a+2b  \\    1 & a & a+b  \\    1 & a+2b & a  \\ \end{matrix}\, \right|\] Operate \[{{R}_{3}}\to {{R}_{3}}-{{R}_{1}}\], \[{{R}_{2}}\to {{R}_{2}}-{{R}_{1}}\] = \[3\,(a+b)\,\left| \,\begin{matrix}    1 & a+b & a+2b  \\    0 & -b & -b  \\    0 & b & -2b  \\ \end{matrix}\, \right|\]          \[=3(a+b)\,(2{{b}^{2}}+{{b}^{2}})=9{{b}^{2}}(a+b)\].


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