A) 0
B) - 39
C) 96
D) 57
Correct Answer: A
Solution :
Applying \[{{C}_{3}}\to {{C}_{3}}-{{C}_{2}}\]and \[{{C}_{2}}\to {{C}_{2}}-{{C}_{1}}\], we get \[\left| \,\begin{matrix} 13 & 3 & 3 \\ 14 & 3 & 3 \\ 15 & 3 & 3 \\ \end{matrix}\, \right|=0\] , \[\{\because {{C}_{2}}\equiv {{C}_{3}}\}\].
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