A) \[{{({{a}^{2}}+{{b}^{2}}+{{c}^{2}})}^{\frac{1}{2}}}\]
B) \[{{\left[ \frac{3}{2}({{a}^{2}}+{{b}^{2}}+{{c}^{2}}) \right]}^{\frac{1}{2}}}\]
C) \[{{\left[ \frac{1}{2}({{a}^{2}}+{{b}^{2}}+{{c}^{2}}) \right]}^{\frac{1}{2}}}\]
D) None of these
Correct Answer: D
Solution :
Applying \[{{A}^{-1}}=\frac{1}{-2}\,\left[ \begin{matrix} -1 & 1 & -1 \\ 8 & -6 & 2 \\ -5 & 3 & -1 \\ \end{matrix} \right]\] \\[{{A}_{32}}=2\] Þ \[{{A}_{22}}=-6\] \[{{A}_{12}}=8,\] Þ \[|A|\,=-2\ne 0\] \[A=\left[ \begin{matrix} 0 & 1 & 2 \\ 1 & 2 & 3 \\ 3 & 1 & 1 \\ \end{matrix} \right]\] Þ \[x=0\] \[AB=\left[ \begin{matrix} 1\times 1+2\times 2+(-1)(0) \\ 3\times 1+0\times 2+2\times 0 \\ 4\times 1+5\times 2+0\times 0 \\ \end{matrix} \right.\] \ \[=\left[ \begin{matrix} 1 & -1 & 0 \\ -2 & 3 & -4 \\ -2 & 3 & -3 \\ \end{matrix} \right]\] and \[A=\left[ \begin{matrix} 1 & 2 & -1 \\ 3 & 0 & 2 \\ 4 & 5 & 0 \\ \end{matrix} \right]\].
You need to login to perform this action.
You will be redirected in
3 sec
