A) \[\pm \sqrt{6}\]
B) \[\pm \sqrt{2}\]
C) \[\pm \sqrt{3}\]
D) \[\sqrt{2},\sqrt{3}\]
Correct Answer: B
Solution :
We have \[\Delta =\left| \,\begin{matrix} -x & 1 & 0 \\ 1 & -x & 1 \\ 0 & 1 & -x \\ \end{matrix}\, \right|\] \[\Delta =-x({{x}^{2}}-1)-1(-x-0)=0\Rightarrow x=\pm \sqrt{2}\]
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