A) \[441\times 446\times 451\]
B) 0
C) - 1
D) 1
Correct Answer: B
Solution :
\[{{A}^{n}}=\left[ \,\begin{matrix} 1 & 2n \\ 0 & 1 \\ \end{matrix}\, \right]\] \[\left\{ {{C}_{1}}\to {{C}_{1}}-{{C}_{2}},\,{{C}_{2}}\to {{C}_{2}}-{{C}_{3}} \right\}\]
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