JEE Main & Advanced Mathematics Sequence & Series Question Bank Exponential series

  • question_answer
    If  \[y=-\left( {{x}^{3}}+\frac{{{x}^{6}}}{2}+\frac{{{x}^{9}}}{3}+..... \right)\], then \[x=\] [MNR 1975]

    A) \[\frac{1+{{e}^{y}}}{3}\]

    B) \[\frac{1-{{e}^{y}}}{3}\]

    C) \[{{(1-{{e}^{y}})}^{1/3}}\]

    D) \[{{(1-{{e}^{y}})}^{3}}\]

    Correct Answer: C

    Solution :

    \[y=-\left\{ {{x}^{3}}+\frac{{{({{x}^{3}})}^{2}}}{2}+\frac{{{({{x}^{3}})}^{3}}}{3}+...... \right\}=\log (1-{{x}^{3}})\] \[\Rightarrow {{e}^{y}}=1-{{x}^{3}}\Rightarrow x={{(1-{{e}^{y}})}^{1/3}}\].


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