A) \[n\]
B) \[1/n\]
C) \[\frac{1}{2}(n+{{n}^{-1}})\]
D) \[\frac{1}{2}({{e}^{n}}+{{e}^{-n}})\]
Correct Answer: C
Solution :
\[1+\frac{{{({{\log }_{e}}n)}^{2}}}{2\,!}+\frac{{{({{\log }_{e}}n)}^{4}}}{4\,!}+....=\frac{{{e}^{{{\log }_{e}}n}}+{{e}^{-{{\log }_{e}}n}}}{2}\] =\[\frac{n+{{n}^{-1}}}{2}\].
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