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JEE Main & Advanced Mathematics Sequence & Series Question Bank Exponential series

  • question_answer
    \[1-x+\frac{{{x}^{2}}}{2\,!}-\frac{{{x}^{3}}}{3\,!}+....\infty =\] [MP PET 1986]

    A) \[{{e}^{x}}\]

    B) \[{{e}^{-x}}\]

    C) \[e\]

    D) \[{{e}^{{{x}^{2}}}}\]

    Correct Answer: B

    Solution :

    \[1-x+\frac{{{x}^{2}}}{2!}-\frac{{{x}^{2}}}{3!}+....\infty ={{e}^{-x}}\].


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