A) \[10\times {{10}^{11}}={{100}^{11}}\]
B) \[{{2}^{3}}\times {{3}^{2}}={{6}^{5}}\]
C) \[{{2}^{3}}>{{3}^{2}}\]
D) \[{{p}^{0}}={{1000}^{0}}\]
Correct Answer: D
Solution :
\[{{p}^{0}}={{(1000)}^{0}}=1\]
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