A) \[25\]
B) \[0\]
C) \[-25\]
D) \[-125\]
Correct Answer: B
Solution :
Since \[{{a}^{o}}=1\] for any 'a', \[\left( {{3}^{0}}-{{4}^{0}} \right)\times {{5}^{-3}}=(1-1)\times {{5}^{-3}}=0\]
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