A) \[(a-4)\,(a-2)={{a}^{2}}+8-6a\]
B) \[(2p+3q)\,(p-q)=2{{p}^{2}}-3{{q}^{2}}\]
C) \[\frac{3{{p}^{2}}}{3{{p}^{2}}}=0\]
D) \[4\,(m-5)=4m-5\]
Correct Answer: A
Solution :
\[(a-4)\,(a-2)={{a}^{2}}-4a-2a+8\] \[={{a}^{2}}-6a+8\] So, the statement in option (A) is correct.
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