A) \[2{{p}^{3}}+7{{p}^{2}}+3p+1\]
B) \[2{{p}^{3}}-7{{p}^{2}}+3p-1\]
C) \[2{{p}^{3}}-7{{p}^{2}}-3p-1\]
D) \[2{{p}^{3}}+7{{p}^{2}}-3p-1\]
Correct Answer: B
Solution :
We have \[(4{{p}^{5}}-14{{p}^{4}}+6{{p}^{3}}-2{{p}^{2}})+2{{p}^{2}}\] \[=\frac{4{{p}^{5}}}{2{{p}^{2}}}-\frac{14{{p}^{4}}}{2{{p}^{2}}}+\frac{6{{p}^{3}}}{2{{p}^{2}}}-\frac{2{{p}^{2}}}{2{{p}^{2}}}\] \[=2{{p}^{3}}-7{{p}^{2}}+3p-1\]
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