JEE Main & Advanced Mathematics Straight Line Question Bank Foot of perpendicular, Transformation, Pedal points Image of a point

  • question_answer
    Coordinates of the foot of the perpendicular drawn from      (0,0) to the line joining \[(a\cos \alpha ,a\sin \alpha )\] and \[(a\cos \beta ,a\sin \beta )\] are  [IIT 1982]

    A)            \[\left( \frac{a}{2},\frac{b}{2} \right)\]

    B)            \[\left[ \frac{a}{2}(\cos \alpha +\cos \beta ),\frac{a}{2}(\sin \alpha +\sin \beta ) \right]\]

    C)            \[\left( \cos \frac{\alpha +\beta }{2},\sin \frac{\alpha +\beta }{2} \right)\]          

    D)            None of these

    Correct Answer: B

    Solution :

               Slope of perpendicular                    = ? \[\left[ \frac{\cos \alpha -\cos \beta }{\sin \alpha -\sin \beta } \right]\] \[=\tan \frac{\alpha +\beta }{2}\]                    Hence equation of perpendicular is                           \[y=\tan \left( \frac{\alpha +\beta }{2} \right)\text{  }x\]                                        ?.. (i)                    Now on solving the equation (i) with the line, we get the required point.               Trick: Take suitable values of \[a,\alpha ,\beta \] and then check with options.


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