A) \[\sqrt{\frac{h}{g}{{\left( \frac{{{m}_{2}}+{{m}_{2}}}{{{m}_{2}}-{{m}_{2}}} \right)}^{2}}}\]
B) \[\sqrt{\frac{h}{g}\left( \frac{{{m}_{1}}+{{m}_{2}}}{{{m}_{1}}-{{m}_{2}}} \right)}\]
C) \[\sqrt{\frac{2h}{g}\left( \frac{{{m}_{2}}+{{m}_{2}}}{{{m}_{2}}-{{m}_{2}}} \right)}\]
D) \[\sqrt{\frac{h}{2g}\left( \frac{{{m}_{2}}+{{m}_{2}}}{{{m}_{2}}-{{m}_{2}}} \right)}\]
Correct Answer: B
Solution :
Since one particle moves by distance\[\frac{h}{2}\], therefore \[\frac{h}{2}=\frac{1}{2}a{{t}^{2}}\] \[\Rightarrow \] \[t=\sqrt{\frac{h}{a}}\] \[\Rightarrow \] \[t=\sqrt{\frac{h}{g}\left( \frac{{{m}_{1}}+{{m}_{2}}}{{{m}_{1}}-{{m}_{2}}} \right)}\]
You need to login to perform this action.
You will be redirected in
3 sec
