9th Class Science Force and laws of motion Question Bank Force and Laws of Motion

  • question_answer
    A body moves along circular path of radius 10 m and the coefficient of friction is 0.5. What should  be its angular velocity in rad/sec if it is not to slip from the surface?\[\left( \text{g }=\text{ 9}.\text{8 m}/{{\text{s}}^{\text{2}}} \right)\]               

    A)  0.1                  

    B)         0.7                     

    C)  5                            

    D)         10                    

    Correct Answer: B

    Solution :

     Since, the centripetal force is supplied by the frictional force, therefore             \[umg=\frac{m{{v}^{2}}}{r}=mr{{w}^{2}}\] \[\Rightarrow \]   \[{{u}_{g}}=r{{\omega }^{2}}\] \[\Rightarrow \]   \[0.5\times 9.8=10\times {{\omega }^{2}}\] \[\Rightarrow \]   \[\omega =\mathbf{0}\mathbf{.7}\,\,\mathbf{rad/sec}\]


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