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9th Class Science Force and laws of motion Question Bank Force and Laws of Motion

  • question_answer
    Three bodies nip \[{{m}_{1}},{{m}_{2}}\] and \[{{m}_{3}}\]nip of mass 10 kg, 20 kg and 30 kg respectively are lying on a frictionless horizontal table and are connected by strings as shown in the figure. These are pulled towards the right with a force of 60 N. Then the tension \[{{T}_{1}},\] and \[{{T}_{2}},\] will respectively be

    A)  10 N, 20 N

    B)  20 N, 20 N

    C)  10 N, 50 N

    D)  10 N, 30 N  

    Correct Answer: D

    Solution :

     If \[a\] be the common acceleration, then             \[{{T}_{1}}={{m}_{1}}a=10a\] and       \[{{T}_{2}}=({{m}_{1}}+{{m}_{2}})a\]             \[=(10+20)a=30a\] So,       \[{{T}_{1}}:{{T}_{2}}=10:30\]


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