A) \[\sqrt{\frac{\upsilon m}{k}}\]
B) \[\sqrt{\frac{\upsilon k}{m}}\]
C) \[u\sqrt{\frac{k}{m}}\]
D) \[u\sqrt{\frac{m}{k}}\]
Correct Answer: D
Solution :
Natural length means at mean position. In this position kinetic energy is maximum. At extreme position, it gets converted entirely into elastic potential energy. \[\frac{1}{2}m{{v}^{2}}=\frac{1}{2}k{{x}^{2}}\]or \[x=\sqrt{\frac{m}{k}}v\]
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