2. Questions Bank
  3. 9th Class
  4. Science
  5. Force and laws of motion

9th Class Science Force and laws of motion Question Bank Force and Laws of Motion

  • question_answer
    A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4. If a force of 2.8 N is applied on the block parallel to the floor, the force of friction between the block and floor \[\left( \text{taking g }=\text{ 1}0\text{ m}/\text{se}{{\text{c}}^{\text{2}}} \right)\] is

    A)  2.8 N  

    B)  8N

    C)  2N

    D)  Zero

    Correct Answer: A

    Solution :

     Force of limiting friction\[={{\mu }_{s}}mg=0.4\times 2\times 10=8\,\,N\] The applied force is less than the force of limiting friction. The block will thus remain in equilibrium. So, the net force on it is zero. So, force of friction is equal to applied force.


You need to login to perform this action.
You will be redirected in 3 sec spinner