question_answer

A tin container is shown in the given figure. There are four circular openings of equal diameter in the side wall of the container. The openings are labelled as I, II, III, and IV. These openings allow the water present in the container to come out through them. The water coming out through opening   ___i___  will fall at the nearest distance from the container, while that coming out through opening   ___ii___  will fall at the farthest distance from the container.

A)   \[i-I,ii-IV\]        

B)   \[i-II,\text{ }ii-III\]

C)  \[i-III,ii-II\]        

D)  \[i-III,ii-II\]

Correct Answer: A

Solution :

  The pressure exerted by a liquid at a point within its volume increases with increasing depth, i.e., liquid pressure decreases with the increasing height of the liquid column. In the given situation, opening I is the topmost, while opening IV is the bottommost. This implies that among the given four openings, the height of the water column is the maximum near I and the minimum near IV. As a result, the water pressure at opening I is the minimum, while that at opening IV is the maximum. Consequently, water will come out with the least force through opening I and with the most force through opening IV. Thus, the water coming out through opening I will fall at the nearest distance from the container, while that coming out through opening IV will fall at the farthest distance from the container. The correct answer is A.