Answer:
The S.I unit of pressure is pascal or \[N{{m}^{2}}.\] The C.G.S. unit of pressure is dyne \[c{{m}^{2}}\]. \[1=\frac{N}{{{m}^{2}}}=?\frac{dyne}{c{{m}^{2}}}\] __________ (1) We know,\[1N={{10}^{5}}\]dyne and \[1\text{ }{{m}^{2}}={{10}^{4}}m{{c}^{2}}\]Substituting the above values in L.H.S of eq. (1), we get, \[\frac{1N}{{{m}^{2}}}=\frac{{{10}^{5}}dyne}{{{10}^{4}}c{{m}^{2}}}=\left( \frac{{{10}^{5}}}{{{10}^{4}}} \right)dyne\,c{{m}^{-2}}\] \[\Rightarrow \]\[1N\text{ }{{m}^{2}}=10\text{ }dyne\text{ }c{{m}^{2}}.\] So, the relation between S.I. and C.G.S unit of pressure is \[1N\text{ }{{m}^{2}}=10\text{ }dyne\text{ }c{{m}^{2}}.\]
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