B 
C 
D 
A) A
B) B
C) A and C
D) B and D
Correct Answer: D
Solution :
Fraction shaded in Figure A =\[\frac{\text{No}\text{. of shaded parts }}{\text{Total no}\text{. of parts}}=\frac{1}{4}\] Fraction shaded in Figure B =\[\frac{\text{No}\text{. of shaded parts }}{\text{Total no}\text{. of parts}}=\frac{2}{4}=\frac{1}{4}\] Fraction shaded in Figure C =\[\frac{\text{No}\text{. of shaded parts }}{\text{Total no}\text{. of parts}}=\frac{3}{4}\] Fraction shaded in Figure D =\[\frac{\text{No}\text{. of shaded parts }}{\text{Total no}\text{. of parts}}=\frac{1}{2}\] So, figure B and & have half part shaded.
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