A) A
B) B
C) C
D) D
Correct Answer: C
Solution :
Fraction=\[\frac{\text{No}\text{. of shade region}}{\text{Total no}\text{. of parts}}\] Figure A shows\[\frac{2}{6}=\frac{1}{3}\]shaded region Figure B shows\[\frac{1}{4}\]shaded region Figure C shows\[\frac{3}{4}\]shaded region Figure D shows\[\frac{2}{4}=\frac{1}{2}\]shaded region \[\frac{1}{3}=\frac{4}{12}\]\[\frac{1}{4}=\frac{3}{12}\]\[\frac{3}{4}=\frac{9}{12}\]\[\frac{1}{2}=\frac{6}{12}\] From least to greatest\[\frac{3}{12}<\frac{4}{12}<\frac{6}{12}<\frac{9}{12}\] \[\Rightarrow \frac{1}{4}\]\[<\frac{1}{3}<\frac{1}{2}<\frac{3}{4}\]
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