A) 1
B) 4
C) 2
D) None of these
Correct Answer: C
Solution :
\[{{\sin }^{2}}\theta +\text{cose}{{\text{c}}^{2}}\theta ={{(\sin \theta +\text{cosec}\theta )}^{2}}-2\sin \theta \text{ cosec}\theta \] \[={{(2)}^{2}}-2=4-2=2,\]since\[(\sin \theta +\text{cosec}\theta )=2.\]
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