A) 1
B) \[2\sec \theta \]
C) 2
D) \[2\tan \theta \]
Correct Answer: B
Solution :
Given that \[x=\sec \theta +\tan \theta \] \[\Rightarrow \,x+\frac{1}{x}=\sec \theta +\tan \theta +\frac{1}{\sec \theta +\tan \theta }\] \[=\sec \theta +\tan \theta +\sec \theta -\tan \theta =2\sec \theta \]
You need to login to perform this action.
You will be redirected in
3 sec
