A) \[pq=1\]
B) \[\frac{q}{p}=1\]
C) \[q-p=1\]
D) \[q+p=1\]
Correct Answer: D
Solution :
\[p=\frac{2\,\sin \theta }{1+\cos \theta +\sin \theta },\,\,q=\frac{\cos \theta }{1+\sin \theta }\] \[\Rightarrow \,\,p+q=\frac{\cos \theta }{1+\sin \theta }+\frac{2\,\sin \theta }{1+\sin \theta +\cos \theta }\,\Rightarrow \,p+q=1.\]
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