A) \[Zn\]
B) \[F{{e}^{2+}}\]
C) \[N{{i}^{3+}}\]
D) \[C{{u}^{+}}\]
Correct Answer: B
Solution :
\[F{{e}^{+2}}-3{{d}^{6}}4{{s}^{0}}-4\] unpaired \[{{e}^{-}}\].
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