A) \[\left[ Kr \right]3{{d}^{10}}4{{s}^{1}}\]
B) \[\left[ Xe \right]4{{f}^{14}}{{d}^{10}}6{{s}^{1}}\]
C) \[\left[ Kr \right]4{{d}^{10}}5{{s}^{1}}\]
D) \[\left[ Kr \right]4{{d}^{9}}5{{s}^{2}}\]
Correct Answer: C
Solution :
\[[Kr]\,4{{d}^{10}}5{{s}^{1}}\] (atomic no. = 47)
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