A) One primary and two secondary\[-OH\] groups
B) One secondary and two primary\[-OH\] groups
C) Three primary \[-OH\] groups
D) Three secondary \[-OH\] groups
Correct Answer: B
Solution :
\[\underset{C{{H}_{2}}-OH}{\overset{C{{H}_{2}}-OH}{\mathop{\underset{|\,\,\,\,}{\overset{|\,\,\,\,}{\mathop{CH}}}\,-OH\,\,\,}}}\,\] one secondary and two primary alcoholic groups.
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