A) \[125\sqrt{10}\]
B) \[25\sqrt{2}\]
C) 125
D) \[125\sqrt{2}\]
Correct Answer: D
Solution :
Given sequence is \[\sqrt{2},\ \sqrt{10},\ \sqrt{50}........\] Common ratio \[r=\sqrt{5}\], first term \[a=\sqrt{2}\], then \[{{7}^{th}}\] term \[{{t}_{7}}=\sqrt{2}{{(\sqrt{5})}^{7-1}}=\sqrt{2}{{(\sqrt{5})}^{6}}=\sqrt{2}{{(5)}^{3}}=125\sqrt{2}\].
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