A) 6
B) 36
C) \[\frac{4}{9}\]
D) \[\frac{9}{4}\]
Correct Answer: A
Solution :
Accordingly, \[a{{r}^{9}}=9\] and \[a{{r}^{3}}=4\] \[\Rightarrow \]\[{{r}^{3}}=\frac{3}{2}\] and \[a=\frac{8}{3}\]. \[\therefore \]\[{{7}^{th}}\] term \[i.e.\]\[a{{r}^{6}}=\frac{8}{3}{{\left( \frac{3}{2} \right)}^{2}}=6\]. Trick: \[{{7}^{th}}\] term is equidistant from \[{{10}^{th}}\]and \[{{4}^{th}}\] so it will be\[\sqrt{9\times 4}=6\].
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