JEE Main & Advanced Mathematics Sequence & Series Question Bank Geometric Progression

  • question_answer
    The 6th term of a G.P. is 32 and its 8th term is 128, then the common ratio of the G.P. is [Pb. CET 1999]

    A) - 1

    B) 2

    C) 4

    D) - 4

    Correct Answer: B

    Solution :

    \[{{T}_{6}}=32\] and \[{{T}_{8}}=128\Rightarrow a{{r}^{5}}=32\]   .....(i) and \[a{{r}^{7}}=128\]           .....(ii) Dividing (ii) by (i), \[{{r}^{2}}=4\] Þ r = 2.


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