A) 15/23
B) 7/15
C) 7/8
D) 15/7
Correct Answer: B
Solution :
\[3+3\alpha +3{{\alpha }^{2}}+3{{\alpha }^{3}}+..............\infty =\frac{45}{8}\] \[\Rightarrow \]\[3\left[ \frac{1}{1-\alpha } \right]=\frac{45}{8}\]\[\Rightarrow \]\[8=15(1-\alpha )\]\[\Rightarrow \]\[\alpha =\frac{7}{15}\].
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