JEE Main & Advanced Mathematics Sequence & Series Question Bank Geometric Progression

  • question_answer
    The sum can be found of a infinite G.P. whose common ratio is \[r\] [AMU 1982]

    A) For all values of \[r\]

    B) For only positive value of \[r\]

    C) Only for \[0<r<1\]

    D) Only for \[-1<r<1(r\ne 0)\]

    Correct Answer: D

    Solution :

    \[{{S}_{\infty }}=\frac{a}{1-r}\] where \[-1<r<1\ \ i.e.\ |r|\ <1\].


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