JEE Main & Advanced Mathematics Sequence & Series Question Bank Geometric Progression

  • question_answer
    The value of \[{{4}^{1/3}}{{.4}^{1/9}}{{.4}^{1/27}}...........\infty \] is [RPET 2003]

    A) 2

    B) 3

    C) 4

    D) 9

    Correct Answer: A

    Solution :

    \[{{4}^{1/3}}{{.4}^{1/9}}{{.4}^{1/27}}......\infty \] \[\therefore \]\[S={{4}^{1/3+1/9+1/27}}......\infty \] \[\Rightarrow \]\[S={{4}^{\left( \frac{1/3}{1-1/3} \right)}}={{4}^{\frac{1/3}{2/3}}}\]\[\Rightarrow \]\[S={{4}^{1/2}}\]\[\Rightarrow \]\[S=2\].


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