JEE Main & Advanced Mathematics Sequence & Series Question Bank Geometric Progression

  • question_answer
     \[0.5737373......=\] [Karnataka CET 2004]

    A) \[\frac{284}{497}\]

    B) \[\frac{284}{495}\]

    C) \[\frac{568}{990}\]

    D) \[\frac{567}{990}\]

    Correct Answer: C

    Solution :

    Given series 0.5737373?? = 0.5 + 0.073 + 0.00073 = 0.5 + \[\frac{73}{1000}+\frac{73}{100000}+....\] = \[0.5+73\left[ \frac{1}{1000}+\frac{1}{100000}+..... \right]\] = \[0.5+73\left[ \frac{1/1000}{1-\frac{1}{100}} \right]\]=\[0.5+\frac{73}{1000}.\frac{100}{99}=\frac{5}{10}+\frac{73}{990}\] = \[\frac{495+73}{990}=\frac{568}{990}\].


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