A) 16
B) 32
C) 64
D) 0
E) 62
Correct Answer: C
Solution :
(32)(32)1/6(32)1/36......\[\infty \]= \[{{(32)}^{1+\frac{1}{6}+\frac{1}{36}+.....\infty }}\] \[={{(32)}^{\frac{1}{1-(1/6)}}}\]\[={{(32)}^{\frac{1}{5/6}}}={{(32)}^{6/5}}\]\[={{2}^{6}}=64\].
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